Wrong test assertion for Anagram exercise in the rust rack

Exercism Support
1

It seems one of the test assertions is wrong i.e. handles_case_of_greek_letters().
In the test, we have this code block

fn handles_case_of_greek_letters() {
    let word = "ΑΒΓ";
    let inputs = &["ΒΓΑ", "ΒΓΔ", "γβα", "αβγ"];
    let output = anagrams_for(word, inputs);
    let expected = HashSet::from_iter(["ΒΓΑ", "γβα"]);
    assert_eq!(output, expected);
}

when you convert the possible anagrams to lowercase you have the following.

['α', 'β', 'γ'] ['β', 'γ', 'δ'] ['α', 'β', 'γ'] ['α', 'β', 'γ']

please note that word is 'α', 'β', 'γ' (when sorted && converted to lowercase).

This means the expected HashSet should be ["ΒΓΑ", "γβα", "αβγ"] not ["ΒΓΑ", "γβα"] .

2

The instructions say that “a word is not its own anagram” and further say that case is ignored. So I don’t think that “αβγ” is an anagram of “ΑΒΓ”.